#### Am Vor 2 years

Dauer: 16:28

Equations of Motion Made Easy! Newton's Equations of Motion also known as SUVAT equations are explained in detail here. We have compared the upward and downward motion. Try the Top 3 Questions at the end of the video and write your answers & doubts in the comments below!

## KOMMENTARE

## Jasvinder kaur

Thug Life

Vor 24 Minuten## Jasvinder kaur

Manocha academy is the best

Vor 24 Minuten## Jasvinder kaur

Jai hind sir

Vor Stunde## Jasvinder kaur

Jai hin sir

Vor Stunde## Anisiuba Chizimuzo

Thank you sir for the awesome explanation but please can you clear my doubts on the answer to No. 2

Vor 2 Stunden## Anisiuba Chizimuzo

sir thank you for the awesome explanation but please can you clear my doubts on the answer to no. 2

Vor 2 Stunden## Manoj N

1.10 m/s 2.-20 m/s2 3.t=2sec h=5m

Vor 15 Stunden## Sampath Sampath

Sir , one doubt your teaching every subject in physics chemistry biology and maths every lesson . Ok leave , more subjects in monacho academy with clear and good examples .I don't the way of thanking you . Guru mata pita god You are the real teacher I can't talk more because tomorrow exam

Vor 2 Tage## LEGEND GIRI

Me watching on my online class of same topic which i cant understand that my teacher is teacher is teaching but u r Better than her

Vor 2 Tage## Ajay the Ak gamer Ak

Watch my video also please sir

Vor 2 Tage## Ajay the Ak gamer Ak

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Vor 2 Tage## Susanta mohanty

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Vor 3 Tage## Manocha Academy

Glad you like them!

Vor 2 Tage## Muhammad Haris

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Vor 3 Tage## Manocha Academy

Great!!!

Vor 2 Tage## Muhammad Haris

Nice sir Your teaching method is very good

Vor 3 Tage## Manocha Academy

Thanks and welcome

Vor 2 Tage## GAMING WIZARD 1234

thank you sir you are th best

Vor 4 Tage## Sameer Rajawat

Ans 1. v=10m/s Ans 2.a= -0.03m/s2 Ans 3. s=5m ,t=1sec

Vor 4 Tage## Nathan Dias

@Anand Vardhan sharma yes

Vor 2 Tage## Anand Vardhan sharma

Is this the answers of top 3 q ??

Vor 2 Tage## Rukiya Choudhari

Nice sir

Vor 4 Tage## Manocha Academy

Thanks and welcome

Vor 4 Tage## Sagar Mishra

Great editing😇

Vor 5 Tage## Manocha Academy

Thank you so much 🙂

Vor 4 Tage## Addanki Sujata

Super sir

Vor 5 Tage## Manocha Academy

Thanks

Vor 4 Tage## Srinivas S

nice sir

Vor 5 Tage## Manocha Academy

Thanks and welcome

Vor 4 Tage## Happy Physicist

Sir need ur support i too have a physics channel

Vor 5 Tage## AKSHITHA Reddy

Thank you sir

Vor 5 Tage## AKSHITHA Reddy

Wlcme

Vor 4 Tage## Abraham Sam

Q1. V= 10m/s Q2. a = 28.8m/s² Q3. S= 5m

Vor 6 Tage## morlu venkateswarao

👍

Vor 6 Tage## Aditya Bhardwaj

Pls explain little faster

Vor 7 Tage## TRANDS_ _GAMING

1.25 not 0.25

Vor 6 Tage## TRANDS_ _GAMING

Put play backspeed 0.25

Vor 6 Tage## Shivansh Rai

1- 10m/s 2- 20m/s 3- time=1 second, distance =5 metre

Vor 7 Tage## Viznasri Nethala

3. Time =1 second Maximum height reached =5m

Vor 8 Tage## Viznasri Nethala

1. 10m/s square

Vor 8 Tage## sathwik Ramiendi

Super

Vor 8 Tage## Manocha Academy

Thanks

Vor 7 Tage## Ghasitu Saini

Sir you are a very good teacher

Vor 9 Tage## Manocha Academy

Thanks and welcome

Vor 8 Tage## sasi sangeetha

Superb sir...

Vor 9 Tage## Manocha Academy

Thanks a ton

Vor 8 Tage## How to?

9:02 why cant we us the third equation

Vor 9 Tage## Vanya Nema

ans 1 -- (10m/s) ans 2 -- (62km/h) ans 3 -- (s=50m)and(t=10s)

Vor 9 Tage## Abraham Sam

Plz u should have changed the km/h in number 2 to m/s hence the distance mentioned was in metres

Vor 6 Tage## BN renukamba B N Renukamba

Nice sir. I have learnt so easily rather than referring the text book sir. Thank you very much sir

Vor 9 Tage## Manocha Academy

Glad to hear that

Vor 9 Tage## Sabarivasan M

How to find height and time taken sir

Vor 10 Tage## Sabarivasan M

Ans for first sum is 10 m\s

Vor 10 Tage## Aankush Shiledar

the initial speed of the ball is less,it increases in middle and becomes zero at the end

Vor 11 Tage## Aankush Shiledar

is it right sir

Vor 11 Tage## entertaining n.s

thank you sir

Vor 11 Tage## Singara Chary podicheti

please post the answers

Vor 11 Tage## Charan rakesh

Thank you for teaching sir I can understand very thak you very much👍👍👍👍👍

Vor 11 Tage## Amit Sharma

Great effort sir

Vor 11 Tage## Manocha Academy

Thanks and welcome

Vor 11 Tage## Asha Dilta

sir how to find the height of any object🤔🤔

Vor 12 Tage## Arham Habib

sir what if we r travelling in a slope.plzz answer fast cause my exams r day after

Vor 12 Tage## Suryansh Katoch

Sir I Cant Thank you in words for the work you did For us.You not only cleared our doughts but also helped us to Understand it in an interesting way

Vor 12 Tage## Manocha Academy

It's my pleasure

Vor 12 Tage## Shweta Jha

Nice

Vor 12 Tage## Manocha Academy

Thanks

Vor 12 Tage## Vinod Negi

Hindi nahi athi

Vor 13 Tage## Stick

?

Vor Tag## Vimal Pandey

Superb Sir... I am seeing this video in 2020 again... Salute to u

Vor 13 Tage## Manocha Academy

Thanks for watching again

Vor 13 Tage## ༒krishna spaceboy༒

V=U+AT

Vor 14 Tage## KRITIKA GUPTA

sir all your videos are really very very helpful.... thanks for helping us .. and by the way i have subscribed to your channel from.. i guess all devices at my house.....

Vor 14 Tage## Manocha Academy

Thanks and welcome

Vor 13 Tage## KRITIKA GUPTA

sir plz help...... and tell the answer of Q2 which you have given..please

Vor 14 Tage## Mohit Soni

nice efforts

Vor 14 Tage## Manocha Academy

Thanks a lot

Vor 13 Tage## Bilal Muhammed

Sir is a legend

Vor 14 Tage## Manocha Academy

Thanks

Vor 14 Tage## sharal niveditha dsa

Thank you sir 👍 SUPERB Video

Vor 15 Tage## sharal niveditha dsa

@Manocha Academy 😊

Vor 13 Tage## Manocha Academy

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Vor 14 Tage## sarah chacko

thank you so much sir !!

Vor 16 Tage## Manocha Academy

Most welcome!

Vor 15 Tage## Benjamen Iipinge

You are really helpful Thanks 😀

Vor 16 Tage## Manocha Academy

Happy to help!

Vor 15 Tage## DD Kumar

Thank you so much sir.

Vor 17 Tage## divya raghavendra

Thank oh sir for such a good explanation 1)10m/s 2)-2m/s^2 3)h=5m T=2s

Vor 17 Tage## kkr nagula

Hlo sis how did you get these answers

Vor 10 Tage## Aadit Dave

Thank you sir

Vor 18 Tage## Manocha Academy

Welcome

Vor 17 Tage## Subrath Chakraborty

Im having some confusions in solving the 2nd question can someone help me there?

Vor 18 Tage## Huma Sabir

Yes?

Vor 17 Tage## Kondameedi Kalyani

Nice sir

Vor 18 Tage## Manocha Academy

Thanks and welcome

Vor 18 Tage## Linson Paul

Sir please make video of circular motion

Vor 19 Tage## Vaitheswari Jagan

Sir u said for the upward direction the final velocity is zero. Then how did u get 2.24m/s ?

Vor 19 Tage## Unami Moremi

Thank u sir

Vor 9 Tage## Vaitheswari Jagan

@Ankit Subedi thank you so much

Vor 15 Tage## Ankit Subedi

In reference of time, if you will increase the magnitude of time then the final velocity will be zero. To be more clear, please keep final velocity=0 m/s, initial velocity=5 m/s [as per video] and acceleration =-10 m/s^2. Then, the time you got is the time taken by the ball to reach the maximum height. And for upward direction, the final velocity is 0 only if it has travelled the maximum distance.

Vor 18 Tage## Deepak Kumar

Hindi is also a language to speak

Vor 19 Tage## Manocha Academy

I have same video in Hindi. You can search for Equations of Motion in Hindi.

Vor 19 Tage## Anshu Sinha

https://youtu.be/9cvGyymlTG0

Vor 20 Tage## Reaxtion

Hi

Vor 20 Tage## Adharsh Gopalakrishnan

Nice explaination

Vor 20 Tage## scout cardinal

You are amazing !!!

Vor 20 Tage## Manocha Academy

Wow, thank you!

Vor 20 Tage## PANTHER OP

The problem I'm facing is I can't understand where to put these equations for solving problems can u explain it sir pls?

Vor 21 Tag## GameoMania

@PANTHER OP sure

Vor 19 Tage## PANTHER OP

@GameoMania OK bro you study better OK

Vor 19 Tage## GameoMania

@PANTHER OP tq bro love u

Vor 19 Tage## PANTHER OP

@GameoMania all the best friend all wishes

Vor 19 Tage## GameoMania

😞😞 exams monday

Vor 19 Tage## Harikrisshna K

Q.1 Speed =10m/s Q.2 Retardation=-20 Q.3 Distance= 5m Time=1 sec Thanks a lot for helping me understand sir.Do keep up the good work👍

Vor 21 Tag## Jarupla Yashwanth

SIR U COVERED HALF OF THE KINEMATICS TOPIC IN 15 MINUTES @ MISHRUTHA

Vor 21 Tag## Jarupla Yashwanth

BYE

Vor 21 Tag## Jarupla Yashwanth

ALSO THANKS FOR THE EXAM TIP SIR

Vor 21 Tag## Manocha Academy

Most welcome

Vor 21 Tag## Jarupla Yashwanth

SIR NO ONE SAYS THAT I DONT KNOW EQUATIONS OF MOTION AFTER SEEING THIS VIDEO SIR PLZ MAKE A VIDEO ON SCALARS AND VECTORS

Vor 21 Tag## Karan Kumar singh

I read in class9

Vor 21 Tag## Karan Kumar singh

Keep it up sir

Vor 21 Tag## Manocha Academy

We will

Vor 21 Tag## Karan Kumar singh

Wah sir really I like your practically teaching

Vor 21 Tag## Manocha Academy

Thanks and welcome

Vor 21 Tag## ABDUL YAZEED

Nice Explanation 😍

Vor 21 Tag## Manocha Academy

Thank you 🙂

Vor 21 Tag## Sunandita Dutta

Ans 1- 10 m/s2 Ans 2- (-20) m/s Ans 3- s =5m t =1sec

Vor 22 Tage## RAUNAK RAJ DUGGAL 210278

Nice explanation 👍

Vor 22 Tage## The Gaming Studio

sir today is my test...and i was having a great difficulty in understanding eqations of motion...u r great sir!!!i never felt physics so easy!!!!!!!!! YOU ARE AWESOME!!!!

Vor 22 Tage## Manocha Academy

Excellent

Vor 20 Tage## Kashish Batra

Sir u said in upward motion final velocity is zero so why we get 2.24m/s answer for final velocity in numerical??

Vor 23 Tage## STARK GANG

Your Teaching is Very much simple and understanding ! thank You Sir ! make an app for this !

Vor 23 Tage## Penta Bubby

A good explanation sir it is very useful to my exam which I am going to attend tomorrow

Vor 23 Tage## Andhra High School Ongole

Thanks sir for nice chapter

Vor 23 Tage## Manocha Academy

Most welcome

Vor 23 Tage## A and S WHOLE SQUARE

Thank you so much, sir, helped me a lot because tomorrow is my exam 📝📝📝📝📝

Vor 24 Tage## Meena Meena

1. v=10m/s 2. a=-20m/s^2 3. h=5m and t=2 seconds Nice explanation. Thanks

Vor 24 Tage## Sanjay Sumbhate

I want to understand by graph.

Vor 25 Tage## Deheri Tejaraj

Good practical application. It enables student to learn the concept easily

Vor 25 Tage## Manocha Academy

Thanks for liking

Vor 25 Tage## Arshad Studios

Is the 1st sum answer 10ms² ???

Vor 25 Tage## Xplore Classes

#tapeshbehl 👍

Vor 25 Tage## Yariswamy Masineni

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Vor 25 Tage## Prithvi Nag

You help me lots sir thank you so much

Vor 26 Tage## Manocha Academy

Glad to hear that

Vor 25 Tage## Arzoo Malik

Wonderful ❣️ vedio by you It make the topic crystal clear for me

Vor 26 Tage## Manocha Academy

Glad to hear that

Vor 26 Tage## Nimisha Patel

Sir can we call negative acceleration or retardation as decceleration?

Vor 26 Tage## jayshree chaturbhuj

You are great teacher

Vor 26 Tage## Manocha Academy

Thank you! 😃

Vor 26 Tage## AURA SQUAD

Nicely explained sir

Vor 28 Tage## Manocha Academy

Thanks and welcome

Vor 27 Tage## Dhananjay V

Thank you 👍 sir ! For making our life and physics simple !

Vor 28 Tage## Manocha Academy

It's my pleasure

Vor 27 Tage## FIRE BOY GAMER

1.10m/s 2.7.2km/h 3.0 sir what happen if we through a ball with more power is v

Vor 28 Tage## Amarjith A

nice

Vor 28 Tage## Kutyamu tk

1= 10m/s 2= 20m/s square 3= 5m & 1s

Vor 29 Tage## INSANE GAMERS FF

Sir great job your teaching is awesome

Vor 29 Tage## Manocha Academy

Thanks and welcome

Vor 28 Tage## Sap Ato

number 1 =28ms-2

Vor 29 Tage## Sap Ato

thank you dear

Vor 28 Tage## HIMANSHU Singh

Sir can u give solution of 3rd question

Vor 29 Tage## HIMANSHU Singh

I found answer

Vor 3 Tage